can someone look this over i think i may have a error here,
Im planing to use dual drive motor on my x axis with rack and pinion set up
5x9 table.
how does that change this calculation...
rack
S1811Y-RB-1P
24 diametrial pitch 20° pressure angele
Pinion gear = 1” in diameter
One rotation = 1 * pi (3.141) = 3.141 in travel per rotation
Target rapid transverse = 1300 ipm
NEMA 34 HIGH TORQUE STEPPER MOTOR 1810 oz-in,
http://www.kelinginc.net/SMotorstock.htmlRPM of pinion to achieve rapid transverse = 1300 / 3.141 = 413.88 ~ 414 rpm
Estimate stepper RPM = 3000 rpm
Required reduction ratio = 3000 / 414= 7.24:1 ratio
Available peak servo torque = 1810 oz-in
Torque output of reduction gearbox = 1810* 7.2 = 13032 oz-in
Torque at radius of pinion gear = 13032/ (7.2 / 2)
.........................................= 13032/ 3.6 = 3620 N
Acceleration = F = m * a
Available peak force at pinion radius = 3620 N
Estimated mass of gantry = ~150 lbs
3620 = 150 * ?
= 3620 / 150
= 24.133 ipm
Target rapid transverse = 1300ipm
Time to achieve rapid transverse = 1300 / 24.133 = 53.86 sec
how do i calculate my resolution?