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1

Week 6

: Chapter 7

Exercises:

Reading

Answer the \why?" at the top of 156 (it's ok to not write this out, just make sure you

know the answer).

7.1.1-7.1.4.

A remark on 7.1.4: it is common to write

n

k

:=

!

n

k

!(n

k

)!

:

This is read as \n choose k". It gets this name because the number produced is the

amount of distinct ways to choose k elements from the set f1; 2; : : : ; ng. If you'd like

an extra challenge,

try to show this. More formally, for 0 k n, you need to show

n

there are k injective functions from the set f1; 2; : : : ; kg to the set f1; 2; : : : ; ng. Doing

this formally is quite dicult, but see if you can understand why it is true with a careful

counting argument.

I found the formulation of 7.1.5 given in the book to be a bit confusing, so I have reformulated it below. You're free to prove the exercise using my wording or Tao's.

7.1.5 (reformulation): Let m be an integer, and for each j with 1 j k, let (a(nj ) )1

1 n=m

Pk

(j )

is

be a convergent sequence of real numbers. Show that the sequence

j =1 an

n=m

convergent, and

k

X

lim

!1

j =1

n

(j )

xn

=

k

X

j =1

lim x(nj ) :

!1

n

(Hint: Use Theorem 6.1.19 (a) and induct on k).

Exercise 1.1

(Identities involving nite series). Prove the following equalities hold.

(a) (Triangular Sum) Show that

n

X

i

= 1 + 2 + 3 + ::: + n =

i=1

( + 1)

:

2

n n

Hint: Induct on n.

This sum gets it's name because it corresponds to the number of circles in the gure

below.

1

(b) (Geometric Series) Let x 2 R, x 6= 1. Show that

n

X

i

x

=

1

i=0

n+1

x

1

x

:

(For the case x = 0, we take 00 = 1 in this context).

(c) For a; b 2 R, show

a

n

n

b

= (a

)

n 1

X

b

!

i n i

a b

i=0

Hint: Use various parts of theorem 7.1.11 and lemma 7.1.4 on the right side until it

simplies to the left side.

Note that if n = 2, this result shows a2 b2 = (a b)(a + b).

2

7.2.1-6

7.3.1-3 (You can use exercise 1.1 (b) above in exercise 7.3.2).

7.4.1 (note that f denes a subsequence of (an )1 in this problem).

n=0

7.5.1-3.

Week 7

Reading

: Chapter 8

:

Exercises

8.1.1-9. (only do 8.1.2, if you didn't do the third extra exercise assigned week 1).

(Optional) 8.1.10.

8.2.1-5.

8.3.1-5.

2

3

8.4.1-3.

Show that every well ordered set is totally ordered.

8.5.3, 8.5.8, 8.5.10, 8.5.12-15, 8.5.17-20

Week 8

: Chapter 9

Exercises:

Reading

9.1.1-8, 9.1.13-15.

9.2.1.

9.3.1-5

9.4.1-5, 9.4.7.

9.5.1.

Answer the \why?" given in remark 9.6.6.

9.6.1.

9.7.1-2.

9.8.3-4.

This exercise helps provide context for exercise 9.8.5, and it's also good to know in general.

Prove the following theorem.

(a) If f : [a; b] ! R is monotonically increasing, for each x0 2 [a; b],

limx!x0 f (x) and limx!x0 + exist, and limx!x0 f (x) limx!x0 + f (x).

Hint: Consider supff (x) j x < x0 g for the left limit, and inf ff (x) j x > x0 g for the

right limit.

(b) An analogous result holds if f is monotonically decreasing. State this result, and derive

it from (a) (instead of mimicking the technique of (a) to prove it directly).

(c) If f : [a; b] ! R is monotone, then f has at most countably many discontinuities.

Hint: Assume without loss of generality f is monotonically increasing. Let A =

fx0 2 [a; b] j f is discontinuous at x0g. By (a), x0 2 A if and only if limx!x0 f (x) <

limx!x0 + f (x). Using this, there's a way to nd an injection from A to Q.

Theorem 3.1.

9.8.5.

9.9.1-5.

9.10.1.

3

4

Week 9

: Chapter 10

Exercises:

Reading

10.1.2-5.

Give a solution to 10.1.5 which does not rely on induction, using exercise 1.1 (c) above.

5

Let f : X ! R, x0 2 X , and L 2 R. Show f is dierentiable at x0 with f 0 (x0 ) = L if and

only if limh!0 f (x0 +hh) f (x0 ) = L.

10.1.6-7.

10.2.1, 10.2.4-7.

10.3.1, 10.3.4-5.

10.4.1-3.

10.5.1.

Week 10

: Chapter 11

Exercises:

Reading

11.1.1-2, 11.1.4.

11.2.1-4.

11.3.3-5.

11.4.1-2, 11.4.4.

11.5.1.

11.6.1, 11.6.3, 11.6.5.

11.8.1-5.

11.9.1-3.

11.10.1-4.

4

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