### Discussion :: Applied Mechanics - Section 2 (Q.No.4)

Shilpa said: (Jul 18, 2015) | |

Resultant R = sqrt(A2+B2). A = 6. B = 8 substitute A, B. R = sqrt(100). R = 10 N. |

Hari Prasanna said: (May 18, 2016) | |

P = 6. Q = 8. R = (P^2 + Q^2 + 2PQ cosa)^1/2. (where 'a' is the angle between the forces 'P' and 'Q'). So, R = (36 + 64 = 2 * 6 * 8 * cos90)^1/2. Then, R = 10. |

Eeranna said: (Aug 7, 2016) | |

The above explanations are correct. Thanks. |

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