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Author Topic: OK that does it!  (Read 16193 times)

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Re: OK that does it!
« Reply #20 on: December 26, 2007, 01:15:07 PM »
I added it to my list... I am working on some other code but will have a look as soon as I am done.

Thanks
Brian
Fixing problems one post at a time ;)

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Re: OK that does it!
« Reply #21 on: December 26, 2007, 04:01:16 PM »
Thanks Guys,
No hurry on my part, I'm sure you're plenty busy.
The thread as coded is +/-.2" long.
Art is absolutely right ! (I'll bet he gets that a lot.)
L85 works OK,
L88 goes in the wrong direction .5" or so , then reverses and runs toward the spindle about 1" while angling out, then cycle ends normally.
L89                  "                     1"                                       "                                        1.5"
Thanks,
RC

Offline Graham Waterworth

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Re: OK that does it!
« Reply #22 on: December 26, 2007, 04:33:38 PM »
I have sent a new G76 macro to Brian and Art for there approval, if my code is right this should hopefully fix the problem.

Graham.
Without engineers the world stops
Re: OK that does it!
« Reply #23 on: December 26, 2007, 05:11:32 PM »
Which axis is the L angle measured from,  X or Z ?
Reason I ask... would L90 typically pull straight out with no chamfer or taper ?
And would L10 cut a long chamfer or taper towards the chuck ? If so, it's from the Z axis...right ?
If it's from the X axis, L10 would pull out nearly straight away and L80 would cut a long chamfer or taper towards the chuck...would it not ?
The way this is now, L80 cuts a longer taper than L30 does. But L100 pulls out angling away from the chuck over the threads.
I realize something is wrong, I'm
just wanting to know how it is intended to work.
Thanks,
RC

Offline Graham Waterworth

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Re: OK that does it!
« Reply #24 on: December 26, 2007, 05:23:27 PM »
I think the macro was a bit wrong.

I have recoded it to work like the big machines do it.

So the tool now comes out over a rotation angle set by the L word.

L180 will bring the tool out over .5 of a pitch L270 over .75 of the pitch etc.

Graham.
Without engineers the world stops
Re: OK that does it!
« Reply #25 on: December 26, 2007, 05:40:29 PM »
Ahhhh..........angle of ROTATION...never crossed my mind. PERFECT !
That makes more sense.
I assume it will work with a single pulse per rev from the spindle input.
When can I expect it for download ?
Thanks again,
RC

Offline Graham Waterworth

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Re: OK that does it!
« Reply #26 on: December 26, 2007, 05:55:32 PM »
I have sent the macro to Brian and Art, as I do not have the authority to post modified versions of there original code they will decide if it gets into the distribution.

Sorry, its all I can do at the moment.

Graham.
Without engineers the world stops
Re: OK that does it!
« Reply #27 on: December 27, 2007, 06:21:43 AM »
One other thing weird about thread cutting.
When the cut gets to the point where the tool begins to pull out, the Z axis begins to slow as the X axis retracts the tool.
It appears to be making a G1 move at feed rate from the depth of the cut to the C clearance..which slows Z.
Seems like Z speed, in relation to the spindle index, should not change until the C move is done.
At 400 rpm, L45 deg., the X axis doesn't move more than about 30% of full speed. (+/-)
Hopefully, this will be corrected with the change as well.
Regards,
RC
« Last Edit: December 27, 2007, 08:58:50 AM by Overloaded »

Offline ART

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Re: OK that does it!
« Reply #28 on: December 27, 2007, 09:12:33 AM »
RC:

  No, that part sounds normal. The move is a syncronised move at requested feedrate, so as it pulls out, the X ratio is higher so the Z slows down. I dont think anything can be done about that one..

Art
Re: OK that does it!
« Reply #29 on: December 27, 2007, 09:42:27 AM »
Graham,
Macro looks good and will be in the next rev

Thanks for looking at it
Brian
Fixing problems one post at a time ;)

www.newfangledsolutions.com
www.machsupport.com