I obviously haven't read all the posts in this section but wonder if anyone can help me?
I recently bought a Huanyang HY03D023B inverter, which is a 220v input 3.0 KW output VFD.
I could not get it to work, and told the supplier in China that it was a dud. After many days of measuring and them assuring me that it was a minor problem that they could fix easily, they finally said that they couldn't fix it and that they would send me a new inverter (I have to pay another $35 freight
.
The thing that is wrong with it seems to be nothing at all on the output side. It measures very high resistance between all terminals:
The resistance measurements are:
U-V = 4.7 Megaohms (4M7)
U-W = 12.44 Megaohms (12M44)
V-W = 4.82 Megaohms (4M82)
and then, when power is applied:
Measurements across the U-V terminals was 10.6v, Then after pressing start it was 11.1 then after pressing stop it was 10v
Measurements across the U-W terminals was 4.3v, Then after pressing start it was 4.0 then after pressing stop it was 2.6v
Measurements across the V-W terminals was 8.5v, Then after pressing start it was 8.3 then after pressing stop it was 10.6v
As soon as I press the start button I get a fault dL which according to the manual is an output short circuit.
Their suggested course of action for this fault is:
1) Check whether the connection wire of the motor has a short circuit. (The motor is not connected)
2) Check whether the insulation of the output wires is good. (No output wires attached)
3) Send for repair.
So, does anyone have a circuit diagram for this inverter, or better still can anyone advise me what component has failed?
The manual also says that the VFD is fuse protected. I cannot find a fuse anywhere in the box.
Your replies would be much appreciated.