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Author Topic: 10th CNC BBQ this weekend. 4th July 2009 Melbourne Australia  (Read 3791 times)

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Offline Pythagoras

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See here for details.
http://www.cnczone.com/forums/showthread.php?t=81998

Here is a video of a previous BBQ

<a href="http://www.youtube.com/v/vjw2ocUkRXw&amp;hl=en&amp;fs=1&amp;" target="_blank" class="new_win">http://www.youtube.com/v/vjw2ocUkRXw&amp;hl=en&amp;fs=1&amp;</a>


« Last Edit: June 30, 2009, 08:41:09 AM by Pythagoras »
The Pythagorean theorem: The sum of the areas of the two squares on the legs (a and b) equals the area of the square on the hypotenuse (c).     a² + b² = c².

Offline Pythagoras

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Re: 10th CNC BBQ this weekend. 4th July 2009 Melbourne Australia
« Reply #1 on: June 30, 2009, 07:07:57 PM »
Anyone coming?
The Pythagorean theorem: The sum of the areas of the two squares on the legs (a and b) equals the area of the square on the hypotenuse (c).     a² + b² = c².

Offline Greolt

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Re: 10th CNC BBQ this weekend. 4th July 2009 Melbourne Australia
« Reply #2 on: June 30, 2009, 07:17:36 PM »
There are heaps of us coming as you know.  ;D ;D

Perhaps not so many of us locals frequent this forum. Lots of interest over at CNCzone.  :)

Greg

Offline Pythagoras

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Re: 10th CNC BBQ this weekend. 4th July 2009 Melbourne Australia
« Reply #3 on: June 30, 2009, 10:30:01 PM »
Yes you are right, and I did know.
I  just thought I'd round up any stragglers here. :)
Funny that this forum started by an Aussie, is not that popular with the Aussies.
The Pythagorean theorem: The sum of the areas of the two squares on the legs (a and b) equals the area of the square on the hypotenuse (c).     a² + b² = c².

Offline Pythagoras

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Re: 10th CNC BBQ this weekend. 4th July 2009 Melbourne Australia
« Reply #4 on: July 04, 2009, 08:02:32 AM »
Thanks to all those who made the day exceptional.
We had 50 guests and 8 machines.
Here is a link to some pictures taken on today.
http://picasaweb.google.com/shoot.the.cat/Cncbbq1#slideshow/5354552226327772178
The Pythagorean theorem: The sum of the areas of the two squares on the legs (a and b) equals the area of the square on the hypotenuse (c).     a² + b² = c².