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10th CNC BBQ this weekend. 4th July 2009 Melbourne Australia
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Topic: 10th CNC BBQ this weekend. 4th July 2009 Melbourne Australia (Read 3791 times)
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Pythagoras
83
a² + b² = c²
10th CNC BBQ this weekend. 4th July 2009 Melbourne Australia
«
on:
June 30, 2009, 08:27:03 AM »
See here for details.
http://www.cnczone.com/forums/showthread.php?t=81998
Here is a video of a previous BBQ
http://www.youtube.com/v/vjw2ocUkRXw&hl=en&fs=1&
«
Last Edit: June 30, 2009, 08:41:09 AM by Pythagoras
»
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The Pythagorean theorem: The sum of the areas of the two squares on the legs (a and b) equals the area of the square on the hypotenuse (c). a² + b² = c².
Pythagoras
83
a² + b² = c²
Re: 10th CNC BBQ this weekend. 4th July 2009 Melbourne Australia
«
Reply #1 on:
June 30, 2009, 07:07:57 PM »
Anyone coming?
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The Pythagorean theorem: The sum of the areas of the two squares on the legs (a and b) equals the area of the square on the hypotenuse (c). a² + b² = c².
Greolt
956
Re: 10th CNC BBQ this weekend. 4th July 2009 Melbourne Australia
«
Reply #2 on:
June 30, 2009, 07:17:36 PM »
There are heaps of us coming as you know.
Perhaps not so many of us locals frequent this forum. Lots of interest over at CNCzone.
Greg
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Pythagoras
83
a² + b² = c²
Re: 10th CNC BBQ this weekend. 4th July 2009 Melbourne Australia
«
Reply #3 on:
June 30, 2009, 10:30:01 PM »
Yes you are right, and I did know.
I just thought I'd round up any stragglers here.
Funny that this forum started by an Aussie, is not that popular with the Aussies.
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The Pythagorean theorem: The sum of the areas of the two squares on the legs (a and b) equals the area of the square on the hypotenuse (c). a² + b² = c².
Pythagoras
83
a² + b² = c²
Re: 10th CNC BBQ this weekend. 4th July 2009 Melbourne Australia
«
Reply #4 on:
July 04, 2009, 08:02:32 AM »
Thanks to all those who made the day exceptional.
We had 50 guests and 8 machines.
Here is a link to some pictures taken on today.
http://picasaweb.google.com/shoot.the.cat/Cncbbq1#slideshow/5354552226327772178
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The Pythagorean theorem: The sum of the areas of the two squares on the legs (a and b) equals the area of the square on the hypotenuse (c). a² + b² = c².
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