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Rd sharma solutions

CHAPTERS

6. Algebraic Expressions and Identities

8. Division of Algebraic Expressions

9. Linear Equation in One Variable

10. Direct and Inverse Variations

13. Profit Loss Discount and Value Added Tax

15. Understanding Shapes Polygons

16. Understanding Shapes Quadrilaterals

17. Understanding Shapes Special Types Quadrilaterals

20. Area of Trapezium and Polygon

21. Volume Surface Area Cuboid Cube

22. Surface Area and Volume of Right Circular Cylinder

23. Classification And Tabulation Of Data

24. Classification And Tabulation Of Data Graphical Representation Of Data As Histograms

25. Pictorial Representation Of Data As Pie Charts Or Circle Graphs

A cuboidal block of solid iron has dimensions 50 cm, 45 cm, and 34 cm, how many cuboids of size 5 cm by 3 cm by 2 cm can be obtained from this block? Assume cutting causes no wastage.

Given details are,

Dimensions of cuboidal block of iron is = 50cm × 45cm × 34cm

Size of small cuboids cutting from it is = 5cm × 3cm × 2cm

So,

Number of small cuboids that can be cut =

Volume of large iron cuboid/ volume of small cuboid

= (50 × 45 × 34) / (5 × 3 × 2)

= 2550 cuboidal blocks

Algebraic Expressions and Identities

Division of Algebraic Expressions

Linear Equation in One Variable

Profit Loss Discount and Value Added Tax

Understanding Shapes Quadrilaterals

Understanding Shapes Special Types Quadrilaterals

Volume Surface Area Cuboid Cube

Surface Area and Volume of Right Circular Cylinder

Classification And Tabulation Of Data

Classification And Tabulation Of Data Graphical Representation Of Data As Histograms

Pictorial Representation Of Data As Pie Charts Or Circle Graphs

Given details are,

Dimensions of cuboidal block of iron is = 50cm × 45cm × 34cm

Size of small cuboids cutting from it is = 5cm × 3cm × 2cm

So,

Number of small cuboids that can be cut =

Volume of large iron cuboid/ volume of small cuboid

= (50 × 45 × 34) / (5 × 3 × 2)

= 2550 cuboidal blocks

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