# Line slope calculator 4x+3y=35

**Straight line given by points A[5; 5] and B[8; 1]**

## Calculation:

**Slope-intercept form of line:**y = -1.3333x+11.6667

**Canonical form of the line equation:**4x+3y-35 = 0

**Parametric form of the line equation:**

x = 3t+5

y = -4t+5 ; t ∈ R

**Slope:**m = -1.3333

**Slope angle of line: φ =**-53°7'48″ = -0.9273 rad

**X intercept:**x

_{0}= 8.75

**Y intercept:**y

_{0}= q = 11.6667

**Distance line from the origin:**d

_{0}= 7

**The length of the segment AB: |AB| =**5

**Vector: AB =**(3; -4)

**Normal vector: n =**(4; 3)

**Midpoint of the segment AB: M =**[6.5; 3]

**Perpendicular Bisector equation:**3x-4y-7.5 = 0

**Vector OA = (5; 5) ; |OA| = 7.0711**

**Vector OB = (8; 1) ; |OB| = 8.0623**

**Scalar product OA .OB = 45**

**Angle ∠ AOB = 37°52'30″ = 0.661 rad**