I built the circuit earlier tonight but the 82R resistor got very hot and started to smell like it was losing the will to live.
I had taken the precaution of fitting a 1amp fuse, the smallest rating I had, as I was wiring directly to a spare 6amp/hr 12v battery from an alarm system.
I switched off the supply and checked the fuse which was ok and checked the resistance of the 82R which measuered ok.
I then tried again but the same happened, that is the heat and the smell, so I gave up. Whilst the supply was on I did try to detect the 9V but couldn't get a reading.
So, considering that the simulation highlighted this issue, how does a tiny little resistor hold back the pressure of the battery and, if this is a problem, how do I limit potential high currents that might damage some of my components. Ok, my supply is never likely to have the capacity to deliver current like a battery but i'm still curious about the logic.
This is probably a pretty rudimentary question to all you with electronics experience but I am trying to learn as i'm doing the project.
thanks ...Sweep