Messages

1601

General Mach Discussion / Re: 3 dimmensional trim path

« on: May 25, 2008, 04:55:13 AM »

I have sent you a personal message.

Graham.

1602

G-Code, CAD, and CAM discussions / Re: G52 Rapid Positioning Problem

« on: May 25, 2008, 04:32:32 AM »

It looks like an initialisation of the datum change that is causing the problem, if you swap the sequence around its fine.  I will pass this one on to Brian for his comments.

Graham.
 
%
G90
G52 x0 y0

(Contour Outside)
F10
G00 X6.75 Y-.020
G00 Z-.125
G01 X7 Y0
G03 X7.5 Y.5 R.5
G01 Y4
G03 X7 Y4.5 R.5
G01 X6.75 Y4.520
G00 Z.125

(Countersink holes)

G52 X7 Y.75
M98 P100

G52 X7 Y1.75
M98 P100

G52 X7 Y2.75
M98 P100

G52 X7 Y3.75
M98 P100

G52 X0 Y0

M30   (end program)

O100 (SUBROUTINE bore hole .630 diameter, .375" deep)
  G00 x0 y0
  Z.125
  G00 Z-.125
  F3 G01 Z-.25
  F6
  G02 X.057 Y0 R.0285
  G02 X.057 Y0 I0 J0
  G02 X0 Y0 R.0285
  F3 G01 Z-.375
  F6
  G02 X.065 Y0 R.0325
  G02 X.065 Y0 I0 J0
  G02 X0 Y0 R.0325
  G00 Z.125
M99
%

1603

G-Code, CAD, and CAM discussions / Re: G52 Rapid Positioning Problem

« on: May 24, 2008, 05:27:11 PM »

the % sign in Mach depicts the start and end of the nc program, if you are running the program with these in the try removing them.

Graham.


%
G90
G52 x0 y0

(Contour Outside)
F10
G00 X6.75 Y-.020
G00 Z-.125
G01 X7 Y0
G03 X7.5 Y.5 R.5
G01 Y4
G03 X7 Y4.5 R.5
G01 X6.75 Y4.520
G00 Z.125

(Countersink holes)

G52 X7 Y.75
M98 P100

G52 X7 Y1.75
M98 P100

G52 X7 Y2.75
M98 P100

G52 X7 Y3.75
M98 P100

G52 X0 Y0

M30   (end program)

O100 (SUBROUTINE bore hole .630 diameter, .375" deep)
  G00 Z.125 (Remove this line)
  G00 X0 Y0
  G00 Z-.125
  F3 G01 Z-.25
  F6
  G02 X.057 Y0 R.0285
  G02 X.057 Y0 I0 J0
  G02 X0 Y0 R.0285
  F3 G01 Z-.375
  F6
  G02 X.065 Y0 R.0325
  G02 X.065 Y0 I0 J0
  G02 X0 Y0 R.0325
  G00 Z.125
M99
%

1604

General Mach Discussion / Re: 3 dimmensional trim path

« on: May 24, 2008, 05:12:22 PM »

That's not hard to do, 10 mins to program that one. that's a 2D shape with Z axis moves.

Graham.

1605

General Mach Discussion / Re: RTCP and GCode compensation.

« on: May 22, 2008, 04:05:08 AM »

Normally on 5 axis mould and die work where the B and C axis are on a swivel head, you are in effect cutting with a ball on the end of a stick,  this is set in the machine at a known distance from the centre of rotation for both the B and C axis.

This information is then given to the 5 axis CAM software where it can plot movement based on this. 

On a machine with a moving table the same method can be used, the difference is in the CAM software setup.

When you are doing surfaces the CAM software should take care of everything, if you are drilling and tapping holes in different faces then you can program the machine as you would a 3 axis.

Graham.
 

1606

G-Code, CAD, and CAM discussions / Re: Double taper

« on: May 20, 2008, 06:12:04 PM »

Post a picture with some dimensions of what you are trying to achieve.

Graham.

1607

G-Code, CAD, and CAM discussions / Re: Double taper

« on: May 20, 2008, 02:47:16 PM »

make sure you have CV turned off in config.  CV and turning do not go well together. Set config to exact stop mode.

Graham.

1608

G-Code, CAD, and CAM discussions / Re: End Mill Engraving

« on: May 18, 2008, 04:29:02 PM »

You can not use scaling to do this as scaling changes the centres/position of the letters as well as shrinking them.

Graham.

1609

G-Code, CAD, and CAM discussions / Re: Double taper

« on: May 18, 2008, 05:59:31 AM »

Its just basic trig.  its all in degrees, you have to have a starting point somewhere in X and Z.

You can use the biggest dia or the length and an angle. the main point is to work out half the included angle and the length, then double it for diameter.

I do not use the wizards so I can not help you with them.

Graham.

1610

G-Code, CAD, and CAM discussions / Re: Double taper

« on: May 17, 2008, 06:13:54 PM »

SIN of the angle.

e.g.

If taper is 20mm long @ 25 degrees included angle and the small dia is 20mm at Z zero then :-

X=20+((SIN(25/2)*20)*2)  i.e. 20+(((4.3287)*20)*2)
Z=-20

G00 X20 Z1.
G01 Z0 F.2
X28.657 Z-20.

Graham.