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Newfangled Solutions Mach3 Wizards / Reclangular Pocket positioning question
« on: November 26, 2006, 08:14:04 PM »
Hey Crew,
Finally finished off my mill conversion and was cutting a reclangular pocket on the weekend to try out the wizards.
Question I have for you is am I meant to allow for the dimension of the radius of the cutter I am using for the X & Y coordinates when locating the pocket?
I entered tooling information in the table in Mach 3 and it appeared in the tool page.
For the record, I was cutting a pocket 35(l) x 32(w) x 26(d) mm in a billet 60 x 40 x 150 mm using a 10mm 2 flute carbide end mill. I wanted a 4 mm perimeter around three sides so I originally set the X & Y to 4mm and nominated the "Set Position" to the corner I wanted. But when it cut the first pass it was clearly 5mm out. I adjusted the X&Y to 9mm from the same "Set Position" and it came out fine.
Am I doing something wrong here? Have I got the tool set up incorrect? The pocket came out to the exact dimensions and therefore must be allowing for the cutter diameter...so hmm any hints or is it a case of allowing for the radius of the cutter in the X&Y positions?
Any clues would be a great help and cure my curiousity.
Cheers,
Marcus
Finally finished off my mill conversion and was cutting a reclangular pocket on the weekend to try out the wizards.
Question I have for you is am I meant to allow for the dimension of the radius of the cutter I am using for the X & Y coordinates when locating the pocket?
I entered tooling information in the table in Mach 3 and it appeared in the tool page.
For the record, I was cutting a pocket 35(l) x 32(w) x 26(d) mm in a billet 60 x 40 x 150 mm using a 10mm 2 flute carbide end mill. I wanted a 4 mm perimeter around three sides so I originally set the X & Y to 4mm and nominated the "Set Position" to the corner I wanted. But when it cut the first pass it was clearly 5mm out. I adjusted the X&Y to 9mm from the same "Set Position" and it came out fine.
Am I doing something wrong here? Have I got the tool set up incorrect? The pocket came out to the exact dimensions and therefore must be allowing for the cutter diameter...so hmm any hints or is it a case of allowing for the radius of the cutter in the X&Y positions?
Any clues would be a great help and cure my curiousity.
Cheers,
Marcus