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**General Mach Discussion / Re: Formula use in Mach 3 secret**

« **on:**March 17, 2008, 09:50:26 AM »

Graham,

Thanks for your prompt response to my quiry. I am trying to work on the end of a cylinder. Actually I am attempting to do ornamental work on wood boxes and have worked out how to make my cuts on the perimeter including circular work, circles , ellipses, etc, and now am trying to do the same on the end of the cylinder which would actually be the top of these boxes held in a rotary table much like a lathe. I know that I will need some formula to work out the moves . An example of what I am trying to do would be to scribe a circle using the rotary motion of A combined with either Y or Z motion. I do not understand how to use the formula feature in the configuration panels for Mach 3. As I stated previously, I can't seem to get any formula to do anything. I am a newby and the use of the fomula feature is a big mystery. How do I get mach 3 to compensate for the radius of the tool from the center of rotation of the A axis as it scribes a circle that is not concentric to the A axis? I will try the code that you have shown in your post but have to ask what the formulas you listed would do??

Thanks, Woodeye

Thanks for your prompt response to my quiry. I am trying to work on the end of a cylinder. Actually I am attempting to do ornamental work on wood boxes and have worked out how to make my cuts on the perimeter including circular work, circles , ellipses, etc, and now am trying to do the same on the end of the cylinder which would actually be the top of these boxes held in a rotary table much like a lathe. I know that I will need some formula to work out the moves . An example of what I am trying to do would be to scribe a circle using the rotary motion of A combined with either Y or Z motion. I do not understand how to use the formula feature in the configuration panels for Mach 3. As I stated previously, I can't seem to get any formula to do anything. I am a newby and the use of the fomula feature is a big mystery. How do I get mach 3 to compensate for the radius of the tool from the center of rotation of the A axis as it scribes a circle that is not concentric to the A axis? I will try the code that you have shown in your post but have to ask what the formulas you listed would do??

Thanks, Woodeye