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Messages - JSRichards

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1
Hood Said: "see if there is a frequency and Time in Int, I am guessing there is not."

I dont undesrstand what you mean here. Please explain? Thanks!

R.

2
Hello Everyone,
Ive been diagnosing a problem with my machine. Last week a PC power supply went BANG!! and it took something else out along with itself when this happened. Since that time, I have not been able to get the various relays to engage in order for the machine to run.. this where my problem lay.

I have a campbell B/O board. I am not sure if it is functioning as it should. I have been able to trigger all the relays.. So I suspect that its intact. Im missing somethng and I just cant put my finger on it...

Firstly, what exactly is a charge pump and how it is usually incorporated into a safety cct? IE Estop cct?
Please refer to the attached images... Is there anyone out there that might hazard a guess as to what the cheesy cct that ive attached would be? It is powered by 5 v dc from PC Pwr supply
There is a 5 v relay and the three IC are 4N25's. The three transistors are FET's 2n7000's and thi scct is for some sort of optoisolation. It is hooked up in part with the servo drives. (rutex 2010's x 3)

Secondly, As I was investigating the various relays and their functions, I found one on top of the Z axis servo, situated between the motor case and the encoder.. It is a 24 vDC relay and I am not sure of its purpose.. does this sound like a typical placement for a relay? what would its purpose be?  Any insight would be very much appreciated.

Thanks in advance. 

JR.


3
Hello Everyone,
Ive been diagnosing a problem with my machine. Last week a PC power supply went BANG!! and it took something else out along with itself when this happened. Since that time, I have not been able to get the various relays to engage in order for the machine to run.. this where my problem lay.

I have a campbell B/O board. I am not sure if it is functioning as it should. I have been able to trigger all the relays.. So I suspect that its intact. Im missing somethng and I just cant put my finger on it...

Firstly, what exactly is a charge pump and how it is usually incorporated into a safety cct? IE Estop cct?

Secondly, As I was investigating the various relays and their functions, I found one on top of the Z axis servo, situated between the motor case and the encoder.. It is a 24 vDC relay and I am not sure of its purpose.. does this sound like a typical placement for a relay? what would its purpose be?  Any insight would be very much appreciated.

Thanks in advance. 

JR.

4
Did you find it? Was it successful?

JR.

5
hmmmm. I have no idea why the two are different sizes...

I'm in a bad way. My machine has broken down and I'm not sure yet what the problem is... I know Ive looked at a hundred different things.. These XML files should be identical as I haven't really done anything except twiddle with the estop ..and they arent even on the PC attached to the machine.. Even though Mach on the machine behaves in a similar manner at this time.

 if anyone sees something Ive missed or somehow rearranged.. Please let me know.. Thanks..

6
fifth try to upload a bloody file.. is this forum finicky or is it just my PC and connection...?

Anyway.. Here goes... I will rename my xml file JSR1 and the original recipie... that should be unique enough  to upload... ~sigh~
Jsr is the one I created and "original recipe is the file that came when I D/L 'ed Mach3  *(file version 3.043.022)

7
Thanks for the "inputs" guys. Ive been reading section 4 of the mach 3 mill instal config pdf (posted in documentation section of support @ artsoft www)
Figure 4-7 shows a simple cct which uses a 470 ohm resistor...

im a littledslexic at times so this is a bit of a challenge.

Ive attached my xml (Mill1) its identicle to that which is provided when Mach is downloaded...Okay now to go figure out how to post a file...
BRB.

8
Thanks Hood.
This condition exists on three seperate machines.. "right out of the box" so to say..in other words Ive downloaded onto a PC and this is what happens when I follow along step for ste[ with Art in the very first of the introductory vids.  This happens on a new machine as well as "seasoned" ones.  It doesnt matter whether they are programmed Act Hi or Act Lo. I can change the state of Mach regardless of pin assignment.. Is it possible that there is something I am missing?

also is it okay to place jumpers directly between pins on the parallel output on the motherboard? Ie. could i put 5 v dc to an input pin and a ground and/or  as well as short out outputs to any ground between 18 and 25?
-for the purposes of bench testing the signals ...

9
Thanks Dick.
Yeah sense of humor... gotcha!  Mind you I didnt laugh last week when something went BANG!!! Ha!! still havent found the issue, but im getting close.. Once  I sus it out, Im going to completely rebuild the control box. "make it my own" so to say. Looking forward to the challenge!
-unfortunately the machine being down is causing a bit of a twiddle with my business... so.. pitter patter.. gettin' at 'er!

Say Dick,
I just posetd a noob question in the main forum.. Might you be kind enough to have a read?

http://www.machsupport.com/forum/index.php/topic,20288.0.html

Cheers!

JR.

10
HI all,
I'm pretty new to this side of the game. I have a basic knowledge of how mach runs off a parallel port,but before i do something potentially foolish, I'm wondering if someone could give a little direction.

First of all, I just d/l'd mach and licensed it. Its not yet connected to anything. I opened up the ports and pin page, set the e-stop to active low (green tick mark) saved it and returned to the main screen. Port address is good also just in case..
Correct me if I'm am wrong but I should be able to press e-stop and be in a ready state? Correct?
Ive watched Art's video and what he is doing does not match the results that I am experiencing...something is amiss.
If I return to ports and pins and change e-stop to active high (red x) and save settings, when I return to the main screen and press e-stop, I should NOT be able to clear the stop... Is this correct?

the reason I ask is because regardless of the pin setting, Mach will clear the e-stop if I depress the button. Am I missing something?

And lastly,

Ugh.. Is it okay to place a jumper directly into a  printer port? - to activate the e-stop cct? or a limit sw. and if so can whatever input pin that is selected be grounded to any to the pins between 18 and 25? ie.. to e-stop on a campbell b/o board pin 10 port1 to ground.
the reason I ask is because my multimeter is reading 5 v on all pins... -except 18-25... Is this right? I feel that I am missing something and when I realize what that is. I'll feel kinda silly, but enlightened.

I hope this sort of make sense.. I'm really really fresh and green when it comes to this side of things..

Thanks in advance..

JR.

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