Machsupport Forum
G-Code, CAD, and CAM => LazyCam (Beta) => Topic started by: budman68 on November 13, 2007, 09:05:21 PM
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[this pertains to LazyCam Pro 2.58]
Ok, I'm really confused here so I thought I'd throw this out there for you to help out. I've created a .500 diameter circle and would like to cut out the outside diameter, hence the need for an offset. Now first I check the scale and indeed it is .500.
I'm going to use a .125 endmill so I load the tool in the offset screen/tab and choose "outside" in the dropdown box. I clck on "create offset". Now the offset line shows up and enlarges the black border, but when I click to check the scale, it only grew .125 in size. Since it's a diameter, shouldn't it have grown twice the cutter diameter since it has to go around the .500 diameter?
Something isn't right, and it might just be me! lol!
Your thoughts?
Dave
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twice the radious of the cutter. rad .0625 plus dia .500 plus rad .0625 = dia .625
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Thanks so much for your help but I don't understand as that makes no sense to me, shouldn't the offset be for the whole diameter X 2 since I'd like the end result to be .500 and not .375,? The machine ended up cutting just that, .375 diameter just like it showed in the software.
So may I ask how you setup to get the result of .500?
Thanks again,
Dave
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when you outside offset a .500 circle with a .125 cutter lcam will show two circles .500 and .625 then you have to delete the .500 circle before you generate the code.if you don't it will cut both circles.
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Yes sir, I did just that as I watched the video as well. There's still something going on here that I don't understand. I'm going to try and "trick" the software and use a 1/16th cutter and see what happens. That should actually work but I'll have to wait until I get home from work to try it.
It's still not a fix but if it works, I guess it's the best I can do.....Thanks again for your help-
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Ok, success after work today and it was definitely me. I thought I had been deleting the original chain but in fact I wasn't. Thanks again for your help doc, it's appreciated- ;)